AC Fundamentals – 63

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63. A square wave has a period of 60 μs. The first odd harmonic is ________.

(a) 5 kHz
(b) 50 kHz
(c) 500 kHz
(d) 33.33 kHz

Answer
Answer : (b)
Explanation
Explanation :

f = frequency
t = time period

t = 60 μs

f = 1 / t = 16.66 Hz.

Harmonics are multiples of the fundamental frequency and can therefore be expressed as: 2ƒ, 3ƒ, 4ƒ …. and so on.

First odd harmonic = 3 * f = 3 * 16.66 = 49.98~ = 50 kHz.

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