AC Fundamentals – 60

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60. A signal with a 400 μs period has a frequency of ________.

(a) 250 Hz
(b) 2,500 Hz
(c) 25,000 Hz
(d) 400 Hz

Answer
Answer : (b)
Explanation
Explanation :

f = frequency
t = time period

Frequency = cycles per second

f = 1 / t = 1 / 400 * 10^-6 = 10000 / 4 = 2,500 Hz.

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