# AC Fundamentals – 56

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56. If the rms current through a 4.7 kΩ resistor is 4 mA, the peak voltage drop across the resistor is ________.

(a) 4 V
(b) 18.8 V
(c) 26.6 V
(d) 2.66 V

Answer
Answer : (c)
Explanation
Explanation :

R = 4.7 kΩ = 4700 Ω
Irms = 4 mA = 0.004 A

Vrms = Irms * R
Vrms = 0.004 * 4700 = 18.8 V.

Vm = √2 * Vrms
Vm = Vrms * 1.414 = 18.8*1.414 = 26.6 V.

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