# AC Fundamentals – 41

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41. If the rms voltage drop across a 15 kΩ resistor is 16 V, the peak current through the resistor is ________.

(a) 15 mA
(b) 1.5 mA
(c) 10 mA
(d) 1 mA

Explanation
Explanation :

V = 16 V
R = 15 kΩ = 15,000 Ω
Irms = V/R = 16/15,000 = 0.001067 A = 1.067 mA

Imax = 2^1/2 * Irms
Imax = 1.414 * 1.067mA = 1.51 mA

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