Work, Power and Energy – 32

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32. A 3.3 kΩ resistor dissipates 0.25 W. The current is ________.

(a) 8.7 mA
(b) 87 mA
(c) 8.7 µA
(d) 8.7 A

Answer
Answer : (a)
Explanation
Explanation : W = I2R I = square root(W/R) = square root( 0.25/(3.3×1000) ) = 0.0087038828 = 8.7 mA
Subject Name : Electrical Engineering
Exam Name : IIT GATE, UPSC ESE, RRB, SSC, DMRC, NMRC, BSNL, DRDO, ISRO, BARC, NIELIT
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