RL Circuits – 18

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18. A 1.2 kΩ resistor is in series with a 15 mH coil across a 10 kHz ac source. The magnitude of the total impedance is ________.

(a) 152.6 Ω
(b) 1,526 Ω
(c) 1,200 Ω
(d) 942 Ω

Answer
Answer : (b)
Explanation
Explanation :

R = 1.2k ohm = 1.2 * 1000 = 1200 ohm
L = 15mH = 15 * 10^-3 = 0.015H
F = 10kHz = 10 * 1000 = 10,000 Hz

XL = 2πfL = 2 * 3.14 * 10,000 * 0.015 = 942 Ω

Z = √ (R^2 + XL^2) = √ (1200^2 + 942^2) = 1525.86 = 1,526 Ω

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