5555555555
15. When four 1s are taken as a group on a Karnaugh map, the number of variables eliminated from the output expression is ________.
(a) 1
(b) 2
(c) 3
(d) 4
| Subject Name : Electronics Engineering |
| Exam Name : IIT GATE, UPSC ESE, RRB, SSC, DMRC, NMRC, BSNL, DRDO, ISRO, BARC, NIELIT |
| Posts Name : Assistant Engineer, Management Trainee, Junior Engineer, Technical Assistant |
| Electronics & Communication Engineering Books
|
| GATE 2023 Total Info | ENGG DIPLOMA | UGC NET Total Info |
| IES 2023 Total Info | PSUs 2022 Total Info | CSIR UGC NET Total Info |
| JAM 2023 Total Info | M TECH 2023 Total Info | RAILWAY 2022 Total Info |
Related Posts
Minimization Techniques » Exercise - 13. A karnaugh map with 4 variables has : (a) 2 cells (b) 4 cells (c) 8 cells (d) 16 cells- 555555555527. The standard SOP form of the expression is ________. (a) (b) (c) (d)
- 555555555526. For the SOP expression , how many 0s are in the truth table's output column? (a) zero (b) 1 (c) 4 (d) 5
- 555555555514. Mapping the standard SOP expression , we get (a) (A) (b) (B) (c) (C) (d) (D)
- 555555555513. Mapping the SOP expression , we get ________. (a) (A) (b) (B) (c) (C) (d) (D)