BJT – 51

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51. For a properly biased pnp transistor, let IC = 10 mA and IE = 10.2 mA. What is the level of IB?

(a) 0.2 A
(b) 200 mA
(c) 200 A
(d) 20.2 mA

Answer

Answer : (c)

Explanation

Explanation : No answer description available for this question. Let us discuss.

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BJT - 60
555555555560. Calculate ac for IC = 15 mA and VCE = 5 V. (a) 200 (b) 180 (c) 220 (d) None of the above
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BJT - 75
555555555575. dc = ________ (a) IB / IE (b) IC / IE (c) IC / IB (d) None of the above
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