Waveform Coding Techniques – Exercise – 1

1. While demodulating PCM, its is first converted into –

(a)  PAM
(b)  PPM
(c)  PWM
(d)  None of the above

Answer
Answer : (a)
Explanation
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(a) (b) (c) (d) Answer : () [/su_spoiler]
Explanation
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3. While demodulating PCM, its is first converted into –

(a)  PAM
(b)  PPM
(c)  PWM
(d)  None of the above

Answer
Answer : (a)
Explanation
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(a) (b) (c) (d) Answer : () [/su_spoiler]
Explanation
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5. The biggest disadvantage of PCM is :

(a) its inability to handle analog signals
(b) the high error rate which its quantizing noise introduces
(c) its incompatibility with TDM
(d) the large bandwidths that are required for it

Answer
Answer : (d)
Explanation
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6. DM is Preferred because –

(a)  Its requires less power
(b)  Its needs lesser bandwidth
(c)  More than one messages can be transmitted simultaneously over a common channel
(d)  None of these

Answer
Answer : (c)
Explanation
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