Waveform Coding Techniques » Exercise – 1
1. While demodulating PCM, its is first converted into –
(a) PAM
(b) PPM
(c) PWM
(d) None of the above
2. The modulation system inherently most noise resistant is :
(a) FM
(b) PM
(c) PWM
(d) PCM
3. While demodulating PCM, its is first converted into –
(a) PAM
(b) PPM
(c) PWM
(d) None of the above
4. For transmission of normal speech signal, the PCM channel needs a bandwidth :
(a) 2 kHz
(b) 4 kHz
(c) 8 kHz
(d) 64kHz
5. The biggest disadvantage of PCM is :
(a) its inability to handle analog signals
(b) the high error rate which its quantizing noise introduces
(c) its incompatibility with TDM
(d) the large bandwidths that are required for it
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Waveform Coding Techniques » Exercise - 1 5. The biggest disadvantage of PCM is : (a) its inability to handle analog signals (b) the high error rate which its quantizing noise introduces (c) its incompatibility with TDM (d) the large bandwidths that are required for it- Waveform Coding Techniques » Exercise - 1 4. For transmission of normal speech signal, the PCM channel needs a bandwidth : (a) 2 kHz (b) 4 kHz (c) 8 kHz (d) 64 kHz
- Waveform Coding Techniques » Exercise - 1 3. While demodulating PCM, its is first converted into - (a) PAM (b) PPM (c) PWM (d) None of the above
- Waveform Coding Techniques » Exercise - 1 2. The modulation system inherently most noise resistant is : (a) FM (b) PM (c) PWM (d) PCM
- Waveform Coding Techniques » Exercise - 1 6. DM is Preferred because - (a) Its requires less power (b) Its needs lesser bandwidth (c) More than one messages can be transmitted simultaneously over a common channel (d) None of these