Complex Numbers » Exercise – 1
1. Number of solutions to the equation (1 –i)x = 2x is :
(a) 1
(b) 2
(c) 3
(d) no solution
2. If , arg(z) < 0, then arg(-z) – arg(z) =
(a) π
(b) –π/4
(c) –π/2
(d) π/2
3. If ω is an imaginary cube root of unity, then (1 + ω – ω2)7 equals :
(a) 128 ω
(b) 128 ω2
(c) -128 ω
(d) -128 ω2
4. Value of ω1999 + ω299 + 1 is :
(a) 0
(b) 1
(c) -1
(d) 2
5. Principal argument of z = -√3+i is :
(a) 5π/6
(b) π/6
(c) -5π/6
(d) none
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