Complex Numbers » Exercise – 1
3. If ω is an imaginary cube root of unity, then (1 + ω – ω2)7 equals :
(a) 128 ω
(b) 128 ω2
(c) -128 ω
(d) -128 ω2
| Subject Name : Engineering Mathematics |
| Exam Name : IIT GATE, UPSC ESE, RRB, SSC, DMRC, NMRC, BSNL, DRDO, ISRO, BARC, NIELIT |
| Posts Name : Assistant Engineer, Management Trainee, Junior Engineer, Technical Assistant |
| Engineering Mathematics Books |
| GATE 2023 Total Info | ENGG DIPLOMA | UGC NET Total Info |
| IES 2023 Total Info | PSUs 2022 Total Info | CSIR UGC NET Total Info |
| JAM 2023 Total Info | M TECH 2023 Total Info | RAILWAY 2022 Total Info |
Related Posts
Complex Numbers » Exercise - 14. Value of ω1999 + ω299 + 1 is : (a) 0 (b) 1 (c) -1 (d) 2- Complex Numbers » Exercise - 19. If the cube roots of unity are 1,ω,ω2 then 1 + ω + ω2 = (a) 0 (b) 1 (c) -1 (d) ω
- Complex Numbers » Exercise - 17. If z3 – 2z2 + 4z – 8 = 0 then : (a) |z| = 1 (b) |z| = 2 (c) |z| = 3 (d) none
- Fourier Series » Exercise - 1 1. The Fourier transform of product of two time functions [f1(t)f2(t)] is given by : (a) [f1(ω) + f2(ω)] (b) [f1(ω) / f2(ω)] (c) [f1(ω) * f2(ω)] (d) [f1(ω) x f2(ω)]
- Complex Numbers » Exercise - 18. i1 + i2 + i3 + i4 + ……… + i1000 = (a) 0 (b) 1 (c) -1 (d) none