Basic Op Amp Applications – 56

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56. How many op-amps are required to implement this equation? Vo = V1

(a) 2
(b) 3
(c) 4
(d) 1

Answer

Answer : (d)

Explanation

Explanation : No answer description available for this question. Let us discuss.

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Basic Op Amp Applications - 26
555555555526. How many op-amps are required to implement this equation? (a) 2 (b) 3 (c) 4 (d) 1
Tags: basic, op, amp, applications, op-amps, required, implement, equation, electronics, engineering
Basic Op Amp Applications - 30
555555555530. How many op-amps are required to implement this equation? (a) 2 (b) 3 (c) 4 (d) 1
Tags: basic, op, amp, applications, op-amps, required, implement, equation, electronics, engineering
Basic Op Amp Applications - 33
555555555533. How many op-amps are required to implement this equation? (a) 2 (b) 3 (c) 4 (d) 1
Tags: basic, op, amp, applications, op-amps, required, implement, equation, electronics, engineering
Basic Op Amp Applications - 28
555555555528. Calculate the output voltage Vo if V1 = –V2 = 300 mV. (a) 0 V (b) –6 V (c) 6 V (d) –8 V
Tags: basic, op, amp, applications, vo, electronics, engineering
Basic Op Amp Applications - 17
555555555517. Calculate the output voltage. (a) 3.02 V (b) 2.03 V (c) 1.78 V (d) 1.50 V
Tags: basic, op, amp, applications, electronics, engineering

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