Number Systems – 72

5555555555

72. How many binary digits are required to count to 10010?

(a) 7
(b) 2
(c) 3
(d) 100

Answer
Answer : (a)
Explanation
Explanation : No answer description available for this question. Let us discuss.
Subject Name : Electronics Engineering
Exam Name : IIT GATE, UPSC ESE, RRB, SSC, DMRC, NMRC, BSNL, DRDO, ISRO, BARC, NIELIT
Posts Name : Assistant Engineer, Management Trainee, Junior Engineer, Technical Assistant
Electronics & Communication Engineering Books

GATE 2023 Total InfoENGG DIPLOMAUGC NET Total Info
IES 2023 Total InfoPSUs 2022 Total InfoCSIR UGC NET Total Info
JAM 2023 Total InfoM TECH 2023 Total InfoRAILWAY 2022 Total Info

Related Posts

  • Number Systems - 78555555555578. Convert hexadecimal C0B to binary. (a) 110000001011 (b) 110000001001 (c) 110000001100 (d) 110100001011
    Tags: number, systems, binary, electronics, engineering
  • Number Systems - 1135555555555113. What is the resultant binary of the decimal problem 49 + 01 = ? (a) 01010101 (b) 00110101 (c) 00110010 (d) 00110001
    Tags: number, systems, binary, electronics, engineering
  • Number Systems - 52555555555552. The octal number for binary 1101110101110110 is ________. (a) 6545218 (b) 5565618 (c) 1566568 (d) 1565668
    Tags: number, systems, binary, electronics, engineering
  • Number Systems - 51555555555551. The decimal number for octal 748 is ________. (a) 74 (b) 60 (c) 22 (d) 62
    Tags: number, systems, electronics, engineering
  • Number Systems - 50555555555550. The binary number for octal 458 is ________. (a) 100010 (b) 100101 (c) 110101 (d) 100100
    Tags: number, systems, binary, electronics, engineering

LEAVE A REPLY

Please enter your comment!
Please enter your name here