Boolean Algebra – 6

6. Solution of A.0 is :

(a) 1
(b) A
(c) 0
(d) A or 1

Answer

Answer : (c)

Explanation

Explanation : No answer description available for this question. Let us discuss.

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Boolean Algebra - 11
555555555511. Which of the following is a form of DeMorgan's theorem? (a) (b) (c) (d)
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Boolean Algebra - 37
555555555537. Applying DeMorgan's theorem to the expression , we get ________. (a) (b) (c) (d)
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Boolean Algebra - 2
Boolean Algebra » Exercise - 1 2. Simplified form of : (a) (b) (c) (d)
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Boolean Algebra - 50
555555555550. The Boolean expression can be reduced to ________. (a) (b) (c) (d)
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Boolean Algebra - 49
555555555549. The Boolean expression is equal to ________. (a) C (b) D (c) C + D (d) 1
Tags: boolean, algebra, electronics, engineering

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