1. How many bytes are there in :
1111 1011 0111 0100 1010
(a) 2
(b) 3
(c) 2½
(d) 3½
| Subject Name : Electronics Engineering |
| Exam Name : IIT GATE, UPSC ESE, RRB, SSC, DMRC, NMRC, BSNL, DRDO, ISRO, BARC, NIELIT |
| Posts Name : Assistant Engineer, Management Trainee, Junior Engineer, Technical Assistant |
| Electronics & Communication Engineering Books |
| GATE 2023 Total Info | ENGG DIPLOMA | UGC NET Total Info |
| IES 2023 Total Info | PSUs 2022 Total Info | CSIR UGC NET Total Info |
| JAM 2023 Total Info | M TECH 2023 Total Info | RAILWAY 2022 Total Info |
Related Posts
Number Systems » Exercise - 119. The value of base x is : (211)x = (152)8 (a) 5 (b) 6 (c) 7 (d) 8- Number Systems » Exercise - 122. Storage of 8 KB means the following number of bytes : (a) 1000 (b) 1024 (c) 8192 (d) 9182
- Number Systems » Exercise - 110. Solution of (11001)2 - (10001)2 is : (a) 10000 (b) 01000 (c) 00100 (d) 00001
- 555555555591. Convert the following decimal number to 8-bit binary.35 (a) 000100102 (b) 000100112 (c) 001000112 (d) 001000102
- 555555555597. Convert the following decimal number to hexadecimal.125 (a) 7D16 (b) D716 (c) 7C16 (d) C716