Waveform Coding Techniques – 1 – 1

1. While demodulating PCM, its is first converted into –

(a) PAM
(b) PPM
(c) PWM
(d) None of the above

Answer
Answer : (a)

Explanation
No answer description available for this question. Let us discuss.

2. The modulation system inherently most noise resistant is :

(a) FM
(b) PM
(c) PWM
(d) PCM

Answer
Answer : (c)

Explanation
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3. While demodulating PCM, its is first converted into –

(a) PAM
(b) PPM
(c) PWM
(d) None of the above

Answer
Answer : (a)

Explanation
No answer description available for this question. Let us discuss.

4. For transmission of normal speech signal, the PCM channel needs a bandwidth :

(a) 2 kHz
(b) 4 kHz
(c) 8 kHz
(d) 64 kHz

Answer
Answer : (d)

Explanation
No answer description available for this question. Let us discuss.

5. The biggest disadvantage of PCM is :

(a) its inability to handle analog signals
(b) the high error rate which its quantizing noise introduces
(c) its incompatibility with TDM
(d) the large bandwidths that are required for it

Answer
Answer : (d)

Explanation
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