Units and Dimensions » Exercise – 2
99. Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimension of permeability is :
(a) M –1 L T –2 A
(b) M L –2 T –2 A –1
(c) M L T –2 A –2
(d) M L T –1 A –1
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