# Frequency Domain Analysis – 1 – 2

6. For the transfer function

$\dpi{100} G(s) H(s) = 1/s (s + 1) (s + 0.5)$

the phase cross-over frequency is :

EXPLANATION

7. A constant N-circle having centre at (- 1/2 + j0) in the G-plane, represents the phase angle equal to :

(a) 180°
(b) 90°
(c) 45°
(d)

EXPLANATION

8. Octave frequency range is given by :

(a) ω1/ω2 = 2
(b) ω1/ω2 = 4
(c) ω1/ω2 = 8
(d)
ω1/ω2 = 10

EXPLANATION

9. The phase angle for the transfer function

$\dpi{100} G(s) = 1/(l + sT) ^{3}$

at corner frequency is :

(a) – 45°
(b) – 90°
(c) – 135°
(d) – 270°

EXPLANATION

10. Frequency response test is not recommended for system with :

(a) very low time constants
(b) with small time constant
(c) with large time constant
(d)
any time constant